Cnd.where("name",in,list)，sql语句出现 where 1!=1，求去掉1!=1或换成1=1

//资金来源统计
Sql sql = dao.sqls().create("InvestmentStatistics.sum");
sql.vars().set("fcOrgId",Cnd.where("fc.belong_id","in",list));
sql.vars().set("riOrgId",Cnd.where("ri.org_id","in",list));

select ri.plan_year_project planYearProject from reporting_info ri WHERE 1 != 1 and ri.year = '2017' and ri.month = '1'

wendal

1楼•2712天前

是 InvestmentStatistics.sum 里面有 1 != 1 吧?

Nooft(qq_dd2c9d2a) 2楼•2712天前

select ( select sum( fs.money ) moneyMonth from funding_source fs left join facility_construct fc on fs.belong_id = fc.id $fcOrgId and fs.input_time < @timeMax and fs.input_time >= @times ) moneyMonth, ( select sum( fs.money ) moneyMonths from funding_source fs left join facility_construct fc on fs.belong_id = fc.id $fcOrgId and fs.input_time < @timeMax and fs.input_time >= @timeMin ) moneyMonths, ( ( select sum( fs.money ) moneyMonth from funding_source fs left join facility_construct fc on fs.belong_id = fc.id $fcOrgId and fs.input_time < @timeMax and fs.input_time >= @times )* 100 /( select ri.plan_year_money planYearMoney from reporting_info ri $riOrgId and ri.year = @year and ri.month = @monthProject ) ) percentageMonth, ( ( select sum( fs.money ) moneyMonth from funding_source fs left join facility_construct fc on fs.belong_id = fc.id $fcOrgId and fs.input_time < @timeMax and fs.input_time >= @timeMin )* 100 /( select ri.plan_year_money planYearMoney from reporting_info ri $riOrgId and ri.year = @year and ri.month = @monthProject ) ) percentageMonths, ( select ri.plan_year_money planYearMoney from reporting_info ri $riOrgId and ri.year = @year and ri.month = @monthProject ) planYearMoney, ( select ri.plan_year_project planYearProject from reporting_info ri $riOrgId and ri.year = @year and ri.month = @monthProject ) planYearProject;

没有

wendal

3楼•2712天前

        Sql sql = Sqls.create("select * from t_user $abc");
        sql.vars().set("abc", Cnd.where("id", "in", new int[]{1,2,3}));
        System.out.println(sql.toString());

输出

select * from t_user  WHERE id IN (1,2,3)

并不会有你说的 1 != 1

Nooft(qq_dd2c9d2a) 4楼•2712天前

谢谢了，我去试试。

Nooft(qq_dd2c9d2a) 5楼•2712天前

是因为里面没有值的原因造成的

wendal

6楼•2712天前

里面没有值是啥意思?

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